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When a RAID-5 array is created, the data is initially zeroed out, and the parity bit is created. You then have a set of RAID-5 disk drives with no data but with a full set of parity bits. From this point on, whenever data is written to a disk drive, both the data disk and the parity disk must be read, then the new data is compared with the old data, and if the data for a particular bit has changed, the parity for that bit must be changed. This is accomplished with an exclusive OR (XOR) operation. Thus, only the data disk and the parity crystal reports barcode font problem Native Crystal Reports Code 39 Barcode - Free Trial Download ... 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Once this operation has been completed, both disk drives must be written out because the parity operation works on entire stripes. Therefore, for each write to a RAID-5 volume, four physical I/O operations occur: two reads (one from data and one from parity) and two writes (back to data and back to parity). However, with a RAID-5 array, the parity is distributed, so this load should be balanced among all the disk drives in the array. This process consists of the following steps: 1. Write to the RAID-5 array occurs. 2. Current data is read from the disk. 3. Current parity is read from the disk. 4. Exclusive Or (XOR) operation is performed on data and new parity is calculated. 5. Data is written out to the disk. 6. Parity is written out to the disk. As you can see, RAID-5 incurs significant overhead on writes. However, reads do not incur any additional overhead (unless a drive has failed). 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